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(Solved): code class="asciimath">1.50\angstrom 1.34\angstrom -83.0--84.2kcalmol^(-1) in comparison to that ...



code class="asciimath">1.50\angstrom 1.34\angstrom -83.0--84.2kcalmol^(-1) in comparison to that of -49.3kcalmol^(-1) for benzene. Explain.



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