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(Solved): The one-to-one function g is defined below. g(x)=(6x-1)/(x+7) Find g^(-1)(x), where g^(-1) is the in ...
The one-to-one function g is defined below.
g(x)=(6x-1)/(x+7)
Find g^(-1)(x), where g^(-1) is the inverse of g.
Also state the domain and range of g^(-1) in interval notation.
g^(-1)(x)=?
Domain of g^(-1) :
Range of g^(-1) :