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(Solved): using the chain rule how do i find the derivative of these f(x)=(x^(2)+1)^(3)-(x^(3)+1)^(2) f(t)=(2 ...
using the chain rule how do i find the derivative of these
f(x)=(x^(2)+1)^(3)-(x^(3)+1)^(2)
f(t)=(2t-1)^(4)+(2t+1)^(4)
f(t)=(t^(-1)-t^(-2))^(3)
f(v)=(v^(-3)+4v^(-2))^(3)
f(x)=\sqrt(x+1)+\sqrt(x-1)
f(u)=(2u+1)^((3)/(2))+(u^(2)-1)^(-(3)/(2))
f(x)=2x^(2)(3-4x)^(4)
h(t)=t^(2)(3t+4)^(3)
f(x)=(x-1)^(2)(2x+1)^(4)
g(u)=\sqrt(u+1)(1-2u^(2))^(8)
f(x)=((x+3)/(x-2))^(3)
f(x)=((x+1)/(x-1))^(5)
s(t)=((t)/(2t+1))^((3)/(2))
g(s)=(s^(2)+(1)/(s))^((3)/(2))