(Solved): write a detailed process description for the hydrodealkylation of toluene to produce benzene \begin ...

\begin{tabular}{|c|c|c|c|c|c|c|c|c|} \hline Stream Number & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline Temperature ( ${}^{?}\mathrm{C}$ ) & 25 & 59 & 25 & 225 & 41 & 600 & 41 & 38 \\ \hline Pressure (bar) & 1.90 & 25.8 & 25.5 & 25.2 & 25.5 & 25.0 & 255 & 23.9 \\ \hline Vapor Fraction & 0.0 & 0.0 & 1.00 & 1.0 & 1.0 & 1.0 & 1.0 & 1.0 \\ \hline Mass Flow (tonne/h) & 10.0 & 13.3 & 0.82 & 20.5 & 6.41 & 20.5 & 0.36 & 9.2 \\ \hline Mole Flow (kmol/h) & 108.7 & 144.2 & 301.0 & 1204.4 & 758.8 & 1204.4 & 42.6 & 1100.8 \\ \hline \multicolumn{9}{|l|}{\begin{tabular}{l} Component Mole Flow \\ $(\mathrm{kmol}/\mathrm{h})$ \end{tabular}} \\ \hline Hydrogen & 0.0 & 0.0 & 286.0 & 735.4 & 449.4 & 735.4 & 25.2 & 651.9 \\ \hline Methane & 0.0 & 0.0 & 15.0 & 317.3 & 302.2 & 317.3 & 16.95 & 438.3 \\ \hline Benzene & 0.0 & 1.0 & 0.0 & 7.6 & 6,6 & 7.6 & 0.37 & 9.55 \\ \hline Toluene & 108.7 & 143.2 & 0.0 & 144.0 & 0.7 & 144.0 & 0.04 & 1.05 \\ \hline \end{tabular} \begin{tabular}{|rrrrrrrrrrr|} \hline 9 & 10 & 11 & 12 & 13 & 14 & 15 & 16 & 17 & 18 & 19 \\ \hline 65.4 & 90 & 147 & 112 & 112 & 112 & 38 & 38 & 38 & 38 & 112 \\ 24.0 & 2.6 & 2.8 & 3.3 & 2.5 & 3.3 & 2.3 & 2.5 & 2.8 & 2.9 & 2.5 \\ 1.0 & 0.0 & 0.0 & 0.0 & 0.0 & 0.0 & 0.0 & 1.0 & 1.0 & 0.0 & 1.0 \\ 20.9 & 11.6 & 3.27 & 14.0 & 22.7 & 22.7 & 8.21 & 2.61 & 0.07 & 11.5 & 0.01 \\ 1247.0 & 142.2 & 35.7 & 185.2 & 290.7 & 290.7 & 105.6 & 304.2 & 4.06 & 142.2 & 0.90 \\ & & & & & & & & & & \\ 652.6 & 0.02 & 0.0 & 0.0 & 0.02 & 0.0 & 0.0 & 178.0 & 0.67 & 0.02 & 0.02 \\ 442.3 & 0.88 & 0.0 & 0.0 & 0.88 & 0.0 & 0.0 & 123.05 & 3.10 & 0.88 & 0.88 \\ 116.0 & 106.3 & 1.1 & 184.3 & 289.46 & 289.46 & 105.2 & 2.85 & 0.26 & 106.3 & 0.0 \\ 36.0 & 35.0 & 34.6 & 0.88 & 1.22 & 1.22 & 0.4 & 0.31 & 0.03 & 35.0 & 0.0 \\ \hline \end{tabular}