1:57 5? 64 knewton.com Thus,
\lim_(x->\infty )(-4x-19)/(3x^(2)-4x 6)=0
. Content attribution Question Evaluate the following limit using L'Hospital's rule.
\lim_(x->\infty )(-3x^(2) 19x-1)/(4x^(2)-6x 5)
Enter an exact answer. Provide your answer below:
\lim_(x->\infty )(-3x^(2) 19x-1)/(4x^(2)-6x 5)=
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