(Solved): 1. a) Calculate the value of standard molar enthalpy and entropy of the chemi ...

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1. a) Calculate the value of standard molar enthalpy and entropy of the chemical reaction at \( 298 \mathrm{~K} \) using the data given: Is the chemical reaction exothermic reaction or not? WHY? \[ \mathrm{ZrO}_{2}(\alpha)+2 \mathrm{CO}(\mathrm{g}) \rightarrow \underline{\mathrm{Zr}}(\alpha)+2 \mathrm{CO}_{2}(\mathrm{~g}) \text { at } 298 \mathrm{~K} \] b) Calculate the enthalpy and entropy of chemical reaction at \( 1600 \mathrm{~K} \). Organize them as we do it in the class. Do not calculate the values! \[ \mathrm{ZrO}_{2}(\beta)+2 \mathrm{CO}(\mathrm{g}) \rightarrow \mathrm{Zr}(\beta)+2 \mathrm{CO}_{2}(\mathrm{~g}) \text { at } 1600 \mathrm{~K} \] DATA: \( \Delta \mathrm{H} \mathrm{Zr}(\alpha \rightarrow \beta)=3900 \) joules at \( 1136 \mathrm{~K} \), \( \Delta \mathrm{H} \mathrm{ZrO}_{2}(\alpha \rightarrow \beta)=5900 \) joules at \( \mathbf{1 4 7 8 K} \) Standard molar enthalpy formation and entropy at 298K: \[ \Delta \mathrm{H}_{\mathrm{f}} \mathrm{ZrO}_{2}(\alpha)=-1,100800 \text { joules, } \mathrm{SZr}(\alpha)=39 \mathrm{~J} / \mathrm{K}, \quad \mathrm{SZrO}_{2}(\alpha)=50.4 \mathrm{~J} / \mathrm{K}, \quad \Delta \mathrm{H}_{1} \mathrm{CO}(\mathrm{g})=-110500 \mathrm{~J} \text {, } \] \[ \mathrm{SCO}(\mathrm{g})=197.5 \mathrm{~J} / \mathrm{K}, \quad \Delta \mathrm{HfCO}_{2}(\mathrm{~g})=-393500 \mathrm{~J}, \mathrm{SCO}_{2}(\mathrm{~g})=213.7 \mathrm{~J} / \mathrm{K} \]