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(Solved): 1 Calculate the enthalpy of solution of NaCl given that the lattice enthalpy of formation of NaCl is ...



1 Calculate the enthalpy of solution of

NaCl

given that the lattice enthalpy of formation of

NaCl

is -771

kJmol^(-1)

and the enthalpies of hydration of sodium and chloride ions are -406 and

-364kJmol^(-1)

respectively. 2 Calculate the enthalpy of hydration of bromide ions given that the hydration enthalpy of barium ions is

-1360kJmol^(-1)

, the lattice enthalpy of formation for

BaBr_(2)

is

-1937kJmol^(-1)

and the enthalpy of solution of

BaBr_(2)=-38kJmol^(-1)

. 3 Calculate the lattice enthalpy of formation of calcium iodide given that its enthalpy of solution is -120

kJmol^(-1)

and the enthalpies of hydration of calcium and iodide ions are -1650 and

-293kJmol^(-1)

respectively. 4 Calculate the enthalpy of solution of the ammonium chloride using this data:

\Delta H_(hyd )(kJmol^(-1)):NH_(4)^(+)-301

;

Cl^(-)-364

; Lattice enthalpy of dissociation

(kJmol^(-1))

: ammonium chloride

+640kJmol^(-1)

.



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