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(Solved): 1. The chart below shows time, position and displacement of another object. Using the definitions ...



1. The chart below shows time, position and displacement of another object.
Using the definitions learned for displacement an

1. The chart below shows time, position and displacement of another object. Using the definitions learned for displacement and average velocity, calculate the object's average velocity, displacement, and total distance traveled between \( \mathrm{t}=33 \mathrm{~min} \) and \( \mathrm{t}=58 \mathrm{~min} \). 2. An object is noted to have the following velocity function \( v(t)=-10 t+3 \) i. Fill in the table below for \( t=0 \) through 6 seconds ii. Graph the velocity function versus time iii. Graph the position function versus time iv. Graph the acceleration function versus time 3. An object launched directly upward with initial speed of \( 20 \mathrm{~m} / \mathrm{s} \) reaches its maximum height at \( t= \) \( \mathrm{t}_{1 / 2} \) and returns to its launch point at \( \mathrm{t}=\mathrm{t}_{\mathrm{f}} \). Graph the velocity versus time for the particle's flight time, clearly labeling the values for \( \mathrm{v}_{0}, \mathrm{t}_{\mathrm{1} / 2}, \mathrm{t}_{\mathrm{f}} \) and \( \mathrm{v}_{\mathrm{f}} \). Use \( \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2} \).


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Average velocity is -0.07km/min Displacement is -1.75 km Total distance travelled is 1.75 km Explanation: Step 1: Average velocity is defined as the t
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