(Solved): 100 mL 0.25 M acetic acid is treated with 0.5 gram activated carbon. After filtering, 17 mL sample i ...

100 mL 0.25 M acetic acid is treated with 0.5 gram activated carbon. After filtering, 17 mL sample is taken from clean solution and is titrated by 0.1025 M NaOH. The amount of NaOH solution used is 35 mL. Find the amount of acetic acid adsorbed by 1 gram of activated carbon.