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(Solved): 2. A particle of mass \( m \) moves in one dimension subject to a potential energy function \( V(x ...



2. A particle of mass \( m \) moves in one dimension subject to a potential energy function \( V(x) \) which has a minimum at

2. A particle of mass \( m \) moves in one dimension subject to a potential energy function \( V(x) \) which has a minimum at \( x=0 \). Given that the force \( F \) is given by \( F=-d V / d x \), in which direction is the force for \( x<0 \) where \( x \) is small? What about \( x>0 \) and still small? Describe the ensuing motion, and the changes in kinetic and potential energy, if you release the particle from rest at some position a small distance from the minimum.


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