(Solved): 2. Saturated Solution Equilibria a. The solubility of sodium chloride at 20C is 358 grams per 10 ...

2. Saturated Solution Equilibria a. The solubility of sodium chloride at $20^{?}\mathrm{C}$ is 358 grams per 1000 grams of water or 358 grams per 1358 grams of solution, which has a density of $1.200\mathrm{g}/\mathrm{mL}$ Calculate the molarity of the saturated $\mathrm{NaCl}$ solution. Equilibrium equation: $\mathrm{NaCl}(s)?={\mathrm{Na}}^{+}(\mathrm{qq})+{\mathrm{Cl}}^{?}(\mathrm{aq})$ Equilibrium constant expression: ${\mathrm{K}}_{\mathrm{sp}}=$ Adding $\mathrm{HCl}$ shifted the reaction Provide a chemical explanation for it. b. Equilibrium equation for saturated ${\mathrm{BaCrO}}_4:{\mathrm{BaCrO}}_4(\mathrm{s})={\mathrm{Ba}}_{(\mathrm{aq})}^{24}+{\mathrm{CrO}}_4{}^2(\mathrm{aq})$ Equilibrium constant expression: ${\mathrm{K}}_{sp}=$ Equation for second equilibrium reaction (addition of acid to saturated ${\mathrm{BaCrO}}_4$ solution) Note how each equilibrium shifts with addition of acid, and provide a chemical explanation for them.