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(Solved): 3.93 When heated, lithium reacts with nitrogen to form lithium nitride: 6Li(s)+N2(g)2Li3 ...




3.93 When heated, lithium reacts with nitrogen to form lithium nitride:
\[
6 \mathrm{Li}(s)+\mathrm{N}_{2}(g) \longrightarrow
3.93 When heated, lithium reacts with nitrogen to form lithium nitride: What is the theoretical yield of in grams when of are heated with of ? If the actual yield of is , what is the percent yield of the reaction?


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To determine the theoretical yield of    and the percent yield of the reaction, we'll follow these steps: Step 1: Calculate the molar masses of Li and N?: Molar mass of Li = 6.94 g/mol Molar mass of N? = 28.02 g/mol

Step 2: Determine the limiting reactant: To determine the limiting reactant, we compare the mole ratios of Li and N? in the balanced equation to the actual amounts given. From the balanced equation, the mole ratio of Li to    is 6:2, and the mole ratio of N? to    The number of moles of Li: moles of Li = mass of Li / molar mass of Li moles of Li = 12.3 g / 6.94 g/mol

The number of moles of N?: moles of N? = mass of N? / molar mass of N? moles of N? = 33.6 g / 28.02 g/mol Now, compare the mole ratios to determine the limiting reactant: Since the mole ratio of Li to    and the mole ratio of N? to   , we can see that N? is the limiting reactant.
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