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(Solved): [3 Points] Implement (i.e get the truth table, then the Boolean function, and finally draw the logi ...



[3 Points] Implement (i.e get the truth table, then the Boolean function, and finally draw the logic diagram) of the followin
[3 Points] Implement (i.e get the truth table, then the Boolean function, and finally draw the logic diagram) of the following functions using AND, OR, and NOT logic gates. Assume A and B are the inputs and is the output. a. has the value of 1 only if: i. has the value 0 and has the value 0 . ii. has the value 0 and has the value 1 . b. has the value of 1 only if: i. has the value 1 and has the value 0 . ii. has the value 0 and has the value 1 .


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We are given a Boolean function F that depends on two inputs A and B. The function has the value of 1 in two cases:


When A has the value 1 and B has the value 0.
When A has the value 0 and B has the value 1.
We need to find the Boolean expression for the function using the logical operators AND, OR, and NOT, and then draw the logic diagram of the expression using logic gates.



To obtain the Boolean expression for the function, we can use the following steps:
For the first case, we need A to be 1 and B to be 0. We can represent this using the logical operator AND as follows: A AND (NOT B). Here, (NOT B) denotes the complement of B, i.e., it is 1 when B is 0, and it is 0 when B is 1.
For the second case, we need A to be 0 and B to be 1. We can represent this also using the logical operator AND as follows: (NOT A) AND B. Here, (NOT A) denotes the complement of A, i.e., it is 1 when A is 0, and it is 0 when A is 1.
Now, we can combine the two cases using the logical operator OR to obtain the final Boolean expression for the function:
F = (A AND (NOT B)) OR ((NOT A) AND B) To draw the logic diagram of the expression, we can use the following steps:
We start by creating a NOT gate for each input that needs to be complemented. In this case, we need to complement B to obtain (NOT B) and we need to complement A to obtain (NOT A).
We then create an AND gate for each term of the expression that involves an AND operator. In this case, we have two terms involving AND, namely A AND (NOT B) and (NOT A) AND B.
Finally, we create an OR gate that takes the output of the two AND gates as inputs and produces the final output F.


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