Home / Expert Answers / Physics / 30-8-energy-density-of-a-magnetic-field-two-horizontal-parallel-wires-are-separated-by-a-distance-d-pa284

(Solved): 30.8 Energy Density of a Magnetic Field Two horizontal parallel wires are separated by a distance d. ...



30.8 Energy Density of a Magnetic Field Two horizontal parallel wires are separated by a distance

d

. If they each carry a current of

I

in opposite directions, what expression gives the energy density of the magnetic field a distance

d

above the top wire?

u_(B)=(9\mu _(0)I^(2))/(32\pi ^(2)d^(2)) u_(B)=(\mu _(0)I^(2))/(32\pi ^(2)d^(2)) u_(B)=(8\mu _(0)I^(2))/(9\pi ^(2)d^(2)) u_(B)=0 u_(B)=(\mu _(0)I^(2))/(16\pi ^(2)d^(2))


We have an Answer from Expert

View Expert Answer

Expert Answer


We have an Answer from Expert

Buy This Answer $5

Place Order

We Provide Services Across The Globe