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[Solved]: "Mgats egbkpnu kple numeeea na o. Tse be Yvon
Home / Expert Answers / Statistics and Probability / 34-mgats-egbkpnu-kple-numeeea-na-o-tse-be-yvonne-kple-zenzile-domet-esiae-ts-k-pa326

(Solved): "Mgats egbkpnu kple numeeea na o. Tse be Yvonne kple Zenzile domet esiae ts k ...



"Mègats? egb?kp?nu kple nume?e?ea na o. Ts?e be Yvonne kple Zenzile domet? ?esia?e ts? ku si ƒe mo le dz?dz?e, si ƒe mo ade to vovo la ƒu gbe zi ?ekaMègakp? egb? o ne menye nenema o la, Mahe To na Wò." Na YY kple ZZ nanye t?tr? siwo wow? le vome siwo fia xexl?dzesi si dzena ?kume kple ?kume le Yvonne kple Zenzile ƒe ku dzi.Megbl? na wò be mègakp? akpa a?eke gb? o ?l? Ay={Y=y},y=1,2,...,6Ay={Y=y},y=1,2,...,6, na nudz?dz? si me dzesi si le Yvonne ƒe ku dzi nye yy, eye nenema ke, . Bz={Z=z},z=1,2,...,6Bz={Z=Le nya siwo gb?na me la, ele be woa?l? ?u?o?owo ?e teƒe ewolia et??, eye woats? ewolia a?l? kuku?e?ewo le esi mè?o nyabiasea ?u o ta Kp? Nyabiase 1Taflatse mègaw?e o. t na egb?kp?nu na x = 2 nye na eye na x 5 nye Na X = max(Y,Z)Megbl? na wò be mègakp? akpa a?eke gb? o Emegbe P(X = x) na x = = 1 nye X = 3 nye , na x = 4 nye Eyata asix?x? si wokp? m? na X nye X nyeSG13 Ðeko mègana nume?e?e a?eke o X si ƒe n?n?me nye , E(X) nye kple standard deviation si nye 7 kple alafa memamã blaat??lia ofYou gbl? nye ?eyi?i to nume?e?e nana me, don 't na nume?e?e".



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