Home / Expert Answers / Computer Science / 8-suppose-the-insertion-sort-algorithm-for-sorting-an-array-has-been-modified-instead-of-sequentia-pa554

(Solved): 8. Suppose the Insertion Sort algorithm for sorting an array has been modified: instead of sequentia ...



8. Suppose the Insertion Sort algorithm for sorting an array has been modified: instead of sequential search, binary search is used to find the position for inserting the next element into the already sorted initial segment of the list.

8. Suppose the Insertion Sort algorithm for sorting an array has been modified: instead of sequential search, binary search i

8. Suppose the Insertion Sort algorithm for sorting an array has been modified: instead of sequential search, binary search is used to find the position for inserting the next element into the already sorted initial segment of the list. 8a. What is the AVERAGE case big-O for the number of **comparisons \( * \star \) (in 1 point terms of the length of the array \( \mathrm{n} \) )? \( O(1) \) \( O(n) \) \( O\left(n^{\wedge} 2\right) \) \( O\left(2^{\wedge} n\right) \) \( \mathrm{O}(\log n) \) \( o(n \log n) \) 8b. What is the WORST case big-0 for the number of \( { }^{\star *} \) comparisons \( ^{\star \star} \) (in 1 point terms of the length of the array \( n \) )? \( \mathrm{O}(1) \) \( O(n) \) \( O\left(n^{\wedge} 2\right) \) \( O\left(2^{\wedge} n\right) \) \( O(\log n) \) \( o(n \log n) \) 8c. What is the BEST case big-0 for the number of \( { }^{\star \star} \) comparisons \( ^{\star \star} \) (in terms 1 point of the length of the array \( n \) )? \( O(1) \) \( O(n) \) \( O\left(n^{\wedge} 2\right) \) \( O\left(2^{\wedge} n\right) \) \( O(\log n) \) \( o(n \log n) \)


We have an Answer from Expert

View Expert Answer

Expert Answer


Insertion Sort algorithm for sorting an array has been modified now : Instead of using linear search to find the location where an element should be i
We have an Answer from Expert

Buy This Answer $5

Place Order

We Provide Services Across The Globe