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(Solved): A=01,B=02,C=03,dots,Z=26.d=307=256+32+16+2+1, find the first letter of the decrypted message by comp ...



A=01,B=02,C=03,dots,Z=26.d=307=256+32+16+2+1, find the first letter of the decrypted message by computing 048^(d)mod713. Now 048^(1),-=a(mod713),048^(2),-=b(mod713),048^(4),-=c(mod713) 048^(8),-=d(mod713),048^(16),-=e(mod713),048^(32),-=f(mod713) 048^(64),-=g(mod713),048^(128)-=h(mod713),048^(256),-=i(mod713) The result is that a= Repeat these computations for each encrypted letter and find the completed decrypted message. Need Help?


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