A=01,B=02,C=03,dots,Z=26.d=307=256+32+16+2+1, find the first letter of the decrypted message by computing 048^(d)mod713. Now
048^(1),-=a(mod713),048^(2),-=b(mod713),048^(4),-=c(mod713)
048^(8),-=d(mod713),048^(16),-=e(mod713),048^(32),-=f(mod713)
048^(64),-=g(mod713),048^(128)-=h(mod713),048^(256),-=i(mod713)
The result is that a=
Repeat these computations for each encrypted letter and find the completed decrypted message.
Need Help?