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(Solved): A)A simple harmonic oscillator with omega = 1.00s ^ - 1 has a position x = 0.25m at t = 0.10s and x ...



A)A simple harmonic oscillator with omega = 1.00s ^ - 1 has a position x = 0.25m at t = 0.10s and x = 0.10m at t = 0.20s What is its position at t = 0.50s Assume a general solution of the form x = C * cos(omega*t + phi) Determine C and from the given positions at various times Then calculate the position at t = 0.50s Show your workB)A simple harmonic oscillator with omega = 1.00s ^ - 1 has a position x = 0.25m at t = 0.10s and x = 0.10m at t = 0.20s What is its position at t=0.50s? Assume a general solution of the form x = A * sin omega*t + B * cos omega*t Determine A and B from the given positions at various times Then calculate the position at t = 0.50s Show your work



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