(Solved): A circuit is constructed with five resistors and one real battery as shown above right. We model. ...

A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf \( V=12 \mathrm{~V} \) in series with an internal resistance \( \mathrm{r} \) as shown above left. The values for the resistors are: \( \mathrm{R}_{1}=\mathrm{R}_{3}= \) \( 31 \Omega, R_{4}=R_{5}=95 \Omega \) and \( R_{2}=92 \Omega \). The measured voltage across the terminals of the batery is \( V_{\text {battery }}=11.57 \mathrm{~V} \). 3) What is \( I_{3} \), the current through resistor \( R_{3} \) ? \( \mathrm{mA} \) Your submissions: Computed value: \( 50.19 \quad \) Submitted: Wednesday, December 7 at \( 9: 13 \) PM Feedback: It looks like you have calculated the current through \( R_{3} \) by assuming the voltage across \( R_{2} \) is equal to the product of \( I_{1} \) and \( R_{2} \). This is not correct. The current through \( R_{2} \) is not equal to \( I_{1} \). Once you properly take care of the currents at the \( R_{1} \) \( R_{2} \cdot R_{3} \) node, I think you can determine the voltage across \( R_{2} \) and then the current through \( R_{3} \). 4) What is \( P_{2} \), the power dissipated in resistor \( R_{2} \) ? \( N \) Your submissions: Computed value: \( 0.435 \quad \) Submitted: Wednesday, December 7 at \( 9: 14 \mathrm{PM} \) Feedback: 5) What is \( V_{2} \), the magnitude of the voltage across the resistor \( R_{2} \) ? Your submissions: Computed value: \( 6.47 \quad \) Submitted: Wednesday, December 7 at 9:14 PM Feedback: