A mass weighing 16 pounds stretches a spring 4 feet. The medium offers a damping force that is numerically equal to 7 times the instantaneous velocity. The mass is initially released 6 feet above the equilibrium position with a downward velocity of
8f(t)/(s)
. (Note:You have to select the correct differential equation and also select the correct initial conditions).(d^(2)x)/(dt^(2))+8x=0(d^(2)x)/(dt^(2))+(7)/(16)(dx)/(dt)+(4)/(16)x=016(d^(2)x)/(dt^(2))+4(dx)/(dt)+7x=0 The initial conditions are
x(0)=-6
and
x^(')(0)=8
x(0)=6
and
x^(')(0)=-8
x(0)=-6
and
x^(')(0)=-8
x(0)=6
and
x^(')(0)=8