A particle has a charge of
3.10\mu C
and moves from point
A
to point
B
, a distance of 0.200 m . The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at
A
and
B
is
EPE_(A)-EPE_(B)= 8.00\times 10^(-4)J
. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences. (a) Number Units (b) Number
?
Units