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(Solved): A singular value decomposition of \( A \) is as follows: \[ A=U \Sigma V^{T}=\left[\begin{array}{c ...



A singular value decomposition of \( A \) is as follows:
\[
A=U \Sigma V^{T}=\left[\begin{array}{cccc}
-0.5 & 0.5 & -0.5 & 0.

A singular value decomposition of \( A \) is as follows: \[ A=U \Sigma V^{T}=\left[\begin{array}{cccc} -0.5 & 0.5 & -0.5 & 0.5 \\ 0.5 & 0.5 & -0.5 & -0.5 \\ 0.5 & 0.5 & 0.5 & 0.5 \\ -0.5 & 0.5 & 0.5 & -0.5 \end{array}\right]\left[\begin{array}{cc} 10 & 0 \\ 0 & 10 \\ 0 & 0 \\ 0 & 0 \end{array}\right]\left[\begin{array}{cc} 0.6 & 0.8 \\ 0.8 & -0.6 \end{array}\right] \] Find the least-squares solution of the linear system \( A \mathbf{x}=\mathbf{b} \), where \( \mathbf{b}=\left[\begin{array}{c}3 \\ -1 \\ -1 \\ 5\end{array}\right] \) \[ \begin{array}{l} \hat{x}_{1}=-\frac{29}{25}, \\ \hat{x}_{2}=-\frac{22}{25} \end{array} \]


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# Given A=U?VT • First find U? U?=[?0.50.5?0.50.50.50.5?0.5?0.50.50.50.50.5?0.50.50.5?0.5][1000100000]=[?0.5(10)+0.5(0)?0.5(0)+0.5(0)?0.5(0)+0.5(10)?0
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