a) What type of transformation occurred between 4-methoxyacetophenone and bleach in acidic conditions? (Hint: This is a reaction that you would have seen in CHM1321). For both starting materials, identify the nucleophile and the electrophile, making sure to highlight the reactive position in each reagent. (2 pts) In acidic conditions the transformation is electrophilic substitution, the reaction between 4-methoxyacetophenone and bleach (NaOCl) results in chlorination of the aromatic ring. The nucleophile is the aromatic ring of 4-methoxyacetophenone, which is electron-rich due to the methoxy group (-OCH?), making the ortho and para positions reactive. The electrophile is the chlorine atom from the bleach, which attacks the ring at the ortho position, leading to the formation of 3-chloro-4-methoxyacetophenone. b) Provide a mechanism for the reaction in acid conditions. (3 pts)