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(Solved): A wheel of diameter 30.0 cm starts from rest and rotates with a constant angular acceleration of 3. ...
A wheel of diameter 30.0 cm starts from rest and rotates with a constant angular acceleration of
3.50ra(d)/(s^(2)). At the instant the wheel has completed its second revolution, compute the radial acceleration of a point on the rim in two ways. Part A Using the relationship
a_(rad)=\omega ^(2)r. Express your answer in meters per second squared.
a_(rad)=|,|(m)/(s^(2))Part B From the relationship
a_(rad)=(v^(2))/(r). Express your answer in meters per second squared.
a_(rad )=,(m)/(s^(2))