(Solved): An agency uses the following formula to determine pavement condition rating, \[ \text { PCR }=96.3 ...

An agency uses the following formula to determine pavement condition rating, \[ \text { PCR }=96.3-5.51(5.0-R O U G H)-1.59 \text { LNALL - } 0.221 \text { AVGOUT - } 0.0306 \text { LONG - } 0.531 \text { TRAN, } \] where we have the following. \[ \begin{aligned} \text { ROUGH } & =\text { roughness measured by present serviceability rating (PSR), scale of } 0 \text { to } 5 \\ \text { LNALL } & =\text { natural logarithm of alligator cracking, ft per mile } \\ \text { AVGOUT } & =\text { outer wheel path rutting (all locations averaged), } 0.01 \text { inch } \\ \text { LONG } & =\text { longitudinal cracking, ft per mile } \\ \text { TRAN } & =\text { transverse cracking, number of cracks per mile } \end{aligned} \] And, present serviceability rating is determined as the following. \[ P S R=5 e^{-0.0051118 \cdot I R I-0.0016027} \] A pavement section has the following distress data. \[ \begin{aligned} \text { IRI } & =106 \mathrm{in} . / \mathrm{mi} \\ \text { Alligator cracking } & =110 \mathrm{ft} / \mathrm{mi} \\ \text { Average rutting } & =0.20 \mathrm{in} . \\ \text { Longitudinal cracks } & =130 \mathrm{ft} / \mathrm{mi} \\ \text { Transverse cracks } & =12 / \mathrm{mi} \end{aligned} \] Determine the current PCR for this section. \[ \text { PCR }= \] in./mi