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(Solved): An oscillator with period \( 3.1 \mathrm{~ms} \) passes through equilibrium at \( t=18.1 \mathrm{~ ...
An oscillator with period \( 3.1 \mathrm{~ms} \) passes through equilibrium at \( t=18.1 \mathrm{~ms} \) with velocity \( v=-4.8 \mathrm{~m} / \mathrm{s} \). The equation of the oscillator's motion is \[ x(t)= \] \( \mathrm{cm} \cos (( \) /s ) \( t+ \) \&)
Expert Answer
Given Time Period, T=3.1ms=3.1×10?3s Passes through equilibrium at , t=18.1ms=18.1×10?3s with velocit