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(Solved): Are male college students more easily bored than their female counterparts? This question was exani ...




Are male college students more easily bored than their female counterparts? This question was exanined in the paper Boredom
(b) Test statistic for the test of hypothesis is given by
(c) What type of distribution would you be using for performing the
Are male college students more easily bored than their female counterparts? This question was exanined in the paper 'Boredom in Young Mdits - Cender. and Cultural Comparisons". The authors administered a scale called the Boredom Proneness Scale to 80 males and 61 fernales uS college students Two random and independent samples are drawn from each group of college students and sample mean scores and sample standard devations hwe been recorded in the table below. Assume the population standard deviations for the scores of males and females: \( \sigma_{1} \) and \( \sigma_{2} \) are UNKNOWN and are NOTEQUAL \( \sigma_{1} \neq \sigma_{2} \). Does the accompanying data support the research hypothesis that the Mean Boredom Proneness Rating is HiGHER for Males than for Fomales? Test the appropriate hypotheses using a \( 2 \% \) level of significance. (a) Stave the null and alternative hypothesis: \( \mathrm{H}_{0} \) \( H_{A} \) (b) Test statistic for the test of typothesis is given by (Round answer to 3 decimal places) (c) What type of datributich would you be uning for pettoming the test? (b) Test statistic for the test of hypothesis is given by (c) What type of distribution would you be using for performing the test? (d) The P.value for the typotheses test \( \mathrm{s} \) Hint: To determine the P.value, you can use Excel function TDIST as follows: =TDisTitest statistic, df, mails majes than for females? Conclude the test and include an interpetation for the fest in the context.


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Given, For males : sample size (n1) = 80 sample mean (x?1) = 10.4 sample standard deviation (s1)= 3.08 For females: sample size (n2) = 61 sample mean (x?2) = 7.8 sample standard deviation (s2) = 3.65 s
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