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At elevated temperatures, potassium chlorate decomposes to yield potassium chloride and oxygen acc ...
At elevated temperatures, potassium chlorate decomposes to yield potassium chloride and oxygen according to the equation: \[ 2 \mathrm{KClO}_{3(s)} \rightarrow 2 \mathrm{KCl}_{(s)}+3 \mathrm{O}_{2(g)} \] When the rate of decomposition of \( \mathrm{KClO}_{3(s)} \) is \( 1.2 \times 10^{-3} \mathrm{M} / \mathrm{s} \), the rate of formation of \( \mathrm{O}_{2}(g) \) is \( \mathrm{M} / \mathrm{s} \). Write your answer as \( 1.2 \mathrm{E}-3 \mathrm{M} / \mathrm{s} \)