Calculate the
E_(cell)value at
298Kfor the cell based on the reaction:
Cu(s)+2Ag^(+)(aq)longrightarrowCu^(2+)(aq)+2Ag(s)where
[Ag^(+)]=0.00100Mand
[Cu^(2+)]=6.25\times 10^(-4)M. The standard reduction potentials are shown below:
Ag^(+)(aq)+e^(-)longrightarrowAg(s),E\deg =0.7996V
Cu^(2+)(aq)+2e^(-)longrightarrowCu(s),E\deg =0.3419V1st attempt
E_(cell )=,V
