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(Solved): calculate the wavelength of a photon emitted by a hydrogen atom when its electron drops from the n=4 ...



calculate the wavelength of a photon emitted by a hydrogen atom when its electron drops from the n=4 state to the n=3 state

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Recall Plancks constant equals \( 6.63 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s} \
Enter your answer in the provided box. Recall Planck's constant equals \( 6.63 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s} \) and the speed of light is \( 3.00 \times 10^{8} \mathrm{~m} / \mathrm{s} \). Calculate the wavelength (in \( \mathrm{nm} \) ) of a photon emitted by a hydrogen atom when its electron drop from the \( n=4 \) state to the \( n=3 \) state.


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Answer : The required wavelength of photon will be 1876 nm Explanation : From Rydberg's formula, we know that 1 / w = RH [ 1/n21 - 1/n22 ] Wher
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