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(Solved): can somoen help put in order? PROOF Order the steps in a proof by contradiction of the statement: " ...



can somoen help put in order?PROOF Order the steps in a proof by contradiction of the statement:
In \( \triangle Q R S \), if \( m \angle Q+m \angle R=90

PROOF Order the steps in a proof by contradiction of the statement: "In \( \triangle Q R S \), if \( m \angle Q+m \angle R=90^{\circ} \), then \( m \angle S=90^{\circ} \)." \[ \begin{array}{l} \equiv \text { and } m \angle S \neq 90^{\circ} \\ \equiv 90+m \angle S=180^{\circ} \end{array} \] \( \equiv \) So, the assumption must be false. \( \equiv \) But this contradicts the given information. \( \equiv \) Using the Substitution Property of Equality, \( \equiv \) So, \( m \angle S=90^{\circ} \) by the Subtraction Property of Equality. \( \equiv \) Assume temporarily that in \( \triangle Q R S, m \angle Q+m \angle R=90^{\circ} \) \( \equiv \) This proves that in \( \triangle Q R S \), if \( m \angle Q+m \angle R=90^{\circ} \), then \( m \angle S=90^{\circ} \). \( \equiv \) By the Triangle Sum Theorem, \( m \angle Q+m \angle R+m \angle S=180^{\circ} \).


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A proof by contradiction is a type of proof that involves assuming that the statement to be proved is false, and then showing that this assumption lea
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