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(Solved): Carbon tetrachloride (CCl4) is diffusing through benzene (C6H6), as the drawing illustrate ...



Carbon tetrachloride \( \left(\mathrm{CCl}_{4}\right) \) is diffusing through benzene \( \left(\mathrm{C}_{6} \mathrm{H}_{6}\
Carbon tetrachloride is diffusing through benzene , as the drawing illustrates. The concentration of at the left end of the tube is maintained at , and the diffusion constant is . The enters the tube at a mass rate of . Using these data and those shown in the drawing. find (a) the mass of per second that passes point and (b) the concentration of at point .


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The given data is as

Concentration of CCl4 at the left end   1.05  10-2 kg/m3
The mass rate (m/t) of CCl4 at the left end   4.90  10-13 kg/s
Diffusion constant   21.8  10-10 m2/s
Cross sectional area at point A   3  10-4 m2

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