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(Solved): Consider the five member truss shown. The members of the truss have a common cross-sectional area, 9 ...
Consider the five member truss shown. The members of the truss have a common cross-sectional area,
9cm^(2), and are made of the same material with elastic modulus,
E=20GPa. This truss is subjected to the following loading:
F_(2)=
1kN,P_(4)=P_(5)=500N.P_(4)and
P_(5)are loaded at
x^(')=
(l_(13))/(4), and
x^(')=(l_(34))/(4)respectively. The lengths of the members are
l_(13)=l_(34)=6mand
l_(23)=3mPage 8 of 9 I Chapter 2: Development of Plane Truss Equations a) List the active degrees of freedom of the system b) write the force to displacement relation for each element in the global coordinate c) Assemble the global equilibrium equation for the active degrees of freedom, directly d) Solve the resulting system of equations for the active degrees of freedom e) Find the strain in each member (element).
