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(Solved): Consider the following contingency table of observed frequencies. Complete parts a, through d beto ...




Consider the following contingency table of observed frequencies. Complete parts a, through d betow.
Click the icon to view t
b. Calculate the expected frequencios for each cell in the contingency table.
jded)
the row and column variables are independ


Contingency table
Consider the following contingency table of observed frequencies. Complete parts a, through d betow. Click the icon to view the contingency table. a. Identify the null and altematwe hypotheses for a chisquare test of independence with based on the intormation in the table This test will have a significance level of a w \( 0.01 \) Choose the correct answor below. A. \( H_{0} \). The variabies \( R_{1}, R_{2}, C_{1}, C_{2} \), and \( C_{3} \) are independont. \( \mathrm{H}_{1} \). At least one of the variablos is not independent. B. \( \mathrm{H}_{0} \). The row and column variables are not independem of one another \( H_{1} \). The row and column varables are independent of one another, C. \( H_{0} \). The variables \( R_{1}, R_{2}, C_{1}, C_{2} \), and \( C_{3} \) are independent. \( \mathrm{H}_{1} \). None of the variables ate independent. D. \( \mathrm{H}_{0} \). The fow and columin varlables are independent of one anothet \( H_{1} \). The tow and column variables are not independent of one anothir: b. Calculate the expected frequencios for each cell in the contingency table. jded) the row and column variables are independent of one another. c. Calculate the chi-nquare test statistic: the row and column variables are not independent of one another. \( x^{2}= \) (Round to two decimal places as needed.) the variablea \( R_{1}, R_{1}, C_{1}, C_{2} \), and \( C_{3} \) are independent d. Determine the p-value. Using o \( =0.01 \), state your conclusions. P.yalue = (Round to three decimal places as needed) none of the variables are independent. Siate your concluslons The p-value is \( \boldsymbol{u}=0.01,50 \) \( H_{0} \) : There is at least one of the variables is not independent. Contingency table


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using excel>add in>phstat>multiple sample test>chi square we have Chi-Square Test Observed Frequencies Column variable Calculations Row variable C1 C2
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