(d) Repeat the preceding hypothesis test using the critical value approach. State the null and alternative hypotheses.
H_(0):\mu <=$1,051
H_(a):\mu >$1,051
H_(0):\mu >=$1,051
H_(a):\mu <$1,051
H_(0):\mu =$1,051
H_(a):\mu !=$1,051
H_(0):\mu >$1,051
H_(a):\mu <=$1,051
H_(0):\mu <$1,051
H_(a):\mu >=$1,051Find the value of the test statistic. (Round your answer to two decimal places.) State the critical values for the rejection rule. (Use
\alpha =0.05. Round your answer to two decimal places. If the test is one-tailed, enter NONE for test statistic
<=test statistic
>=State your conclusion. Reject
H_(0). There is insufficient evidence to conclude that the mean refund of "last minute" filers is less than or equal
$1,051. Do not reject
H_(0). There is sufficient evidence to conclude that the mean refund of "last minute" filers is less than
$1,051. Do not reject
H_(0). There is insufficient evidence to conclude that the mean refund of "last minute" filers is less or equal than
$1,051. Reject
H_(0). There is sufficient evidence to conclude that the mean refund of "last minute" filers is less than
$1,051. Final answer Answers: part a)
H_(0):\mu =1,051
H_(a):\mu <1,051part b)
z=-1.76
P- value =0.0392part c) Reject
H_(0). There is sufficient evidence to conclude that the mean refund of " last minite " filers is less than
$1051