(Solved): Determine the horizontal and vertical components of each vector shown in the Figures below. (i) A. T ...
Determine the horizontal and vertical components of each vector shown in the Figures below. (i) A. The horizontal components are: (i)
v_(x)=19f(t)/(s)*cos143\deg , the negative sign indicates to the left. (ii)
a_(x)=(15*68(m)/(s^(2)))/(\sqrt(8^(2)+15^(2))), to the left. The vertical components are: (i)
v_(y)=19f(t)/(s)*sin143\deg , the positive sign indicates upwards. (ii)
a_(y)=(8*68(m)/(s^(2)))/(\sqrt(8^(2)+15^(2))), upwards. B. The horizontal components are: (i)
v_(x)=19f(t)/(s)*cos(180\deg -143\deg ), the negative sign indicates to the left. (ii)
a_(z)=(15*68(m)/(s^(2)))/(\sqrt(8^(2)+15^(2))), to the left The vertical components are: (i)
v_(y)=19f(t)/(s)*sin(180\deg -143\deg ), the positive sign indicates upwards. (ii)
a_(y)=(8*68(m)/(s^(2)))/(\sqrt(8^(2)+15^(2))), upwards C. The horizontal components are: (i)
v_(x)=19f(t)/(s)*cos(180\deg -143\deg )(ii)
a_(x)=(15*68(m)/(s^(2)))/(\sqrt(8^(2)+15^(2))), to the left. Determine the horizontal and vertical components of each vector in the Figures below. (i) (ii) A. (i) The horizontal and vertical components will be:
(28f(t)/(sec))*cos(245\deg )and
(28f(t)/(sec))*sin(-115\deg ), respectively. (ii) The horizontal and vertical components will be:
(4)/(5)*40Nlarrand
(3)/(5)*40Ndarr, respectively. B. (i) The horizontal and vertical components will be:
-28*cos(115\deg )f(t)/(sec)and
-28*sin(115\deg )f(t)/(sec), respectively. (ii) The horizontal and vertical components will be:
40*sin(53.1\deg )N->and
40*cos(36.9\deg )Ndarr, respectively. C. (i) The horizontal and vertical components will be:
28*cos(115\deg )f(t)/(seclarr)and
28*sin(245\deg )f(t)/(sec)respectively. (ii) The horizontal and vertical components will be:
40*sin(-143\deg )Nlarrand
40*sin(216\deg )Ndarr, respectively. D. (i) The horizontal and vertical components will be:
28*sin(25\deg )f(t)/(seclarr)and
28*sin(65\deg )f(t)/(secdarr), respectively. (ii) The horizontal and vertical components will be:
(3)/(5)*40Nlarrand
(4)/(5)*40Ndarr, respectively. E. (i) The horizontal and vertical components will be:
28*cos(65\deg )f(t)/(seclarr)and
28*cos(25\deg )f(t)/(secdarr), respectively. (ii) The horizontal and vertical components will be:
(5)/(3)*40Nlarrand
(5)/(4)*40Ndarr, respectively. 29
