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(Solved): Determine the margin of error for a confidence interval to estimate the population mean with \( n=4 ...




Determine the margin of error for a confidence interval to estimate the population mean with \( n=42 \) and \( \sigma=46 \) f
Determine the margin of error for a confidence interval to estimate the population mean with \( n=42 \) and \( \sigma=46 \) for the following confidence levels. a) \( 90 \% \) b) \( 94 \% \) c) \( 98 \% \) Click the icon to view the cumulative probabilities for the standard normal distribution. a) With a \( 90 \% \) confidence level, the margin of error is (Round to two decimal places as needed.) b) With a \( 94 \% \) confidence level, the margin of error is (Round to two decimal places as needed.) c) With a \( 98 \% \) confidence level, the margin of error is (Round to two decimal places as needed.)


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Solution : Given that : Population standard deviation = ? = 46 Sample size = n = 42 To Find : Margin of Error (E). a) Confidence level = c = 90% c = 9
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