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(Solved): Diff EQ Solve the initial value problem. t2dtdx+4tx=t6lnt+2,x(1)=0 The solution is x(t)= ...

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Solve the initial value problem.

t^{2} \frac{d x}{d t} + 4 t x = t^{6} ln t + 2, x (1) = 0

The solution is

x (t) =

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