(Solved): DON'T COPY FROM OTHER BECAUSE THEY SOLVED IT WRONG. Design an 8-4-2-1 BCD code converter to drive a ...

DON'T COPY FROM OTHER BECAUSE THEY SOLVED IT WRONG.

Design an 8-4-2-1 BCD code converter to drive a seven-segment indicator. The four inputs to the converter circuit \( (A, B, C \), and \( D) \) represent an 8-4-21 binary-coded-decimal (BCD) digit. The invalid BCD combinations 1010 through 1111 will give "E", error. Design your circuit using minimum number of gates. Test your design using logic work. Use \( \square \) (not \( \square \) ) for 6 Use \( \square \) (not \( \square \) ) for 9 ??89666989 Solve the question using less than 18 gates. And in BCD 8-4-2-1 code if it is from 1010 to 1111 which means from 10 to 15 in dicemal must give the letter " E " in the display. And remember to use less than 18 gates. Pls help