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(Solved): (e) For the Markov Chain in (d), let T=min{n>0|x_(n)=x}. Then E[T|x_(n)|]=[x]= (1)/(\pi (x))<\ ...



(e) For the Markov Chain in (d), let

T=min{n>0|x_(n)=x}

. Then

E[T|x_(n)

|]

=

[

x]=

(1)/(\pi (x))<\infty

. TRUE/FALSE



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