(Solved): Exapmple whats has been done here , explain the line of codes and the given answer . Computer Archit ...

Consider this high-level language statement: $\mathrm{A}=\mathrm{B}+\mathrm{C}/?\text{ assume all quantities in main memory */ }$ With a traditional instruction set architecture, referred to as a complex instruction set computer (CISC), this instruction can be compiled into one processor instruction: $\text{ add mem (B), }\mathrm{mem}(\mathrm{C})\text{, }\mathrm{mem}(\mathrm{A})$ On a typical RISC machine, the compilation would look something like this: load mem(B), $\mathrm{reg}(1)$; load mem (C), $\mathrm{reg}(2)$; add $\mathrm{reg}(1),\mathrm{reg}(2),\mathrm{reg}(3)$; store reg(3), mem (A) Because of the nature of the RISC architecture (discussed in Chapter 15), both machines may execute the original high-level language instruction in about the same time. If this example is representative of the two machines, then if the CISC machine is rated at 1 MIPS, the RISC machine would be rated at 4 MIPS. But both do the same amount of high-level language work in the same amount of time.