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(Solved): Expected Value (Mean) E(x)=\mu =\sum_(all x) (x*P(x))=(2)/(3) Variance Var(x)=\sigma ^(2)=\sum_(all ...



Expected Value (Mean)

E(x)=\mu =\sum_(all x) (x*P(x))=(2)/(3)

Variance

Var(x)=\sigma ^(2)=\sum_(all x) ((x-\mu )^(2)*P(x))=(4)/(9)

Standard Deviation

\sqrt(Var(x))=\sqrt(\sigma ^(2))=\sqrt(\sum_(all x) ((x-\mu )^(2)*P(x)))=()/(?) Input and reduce! \sqrt((4)/(9))


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