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(Solved): Find the interval of convergence of \sum_(n=0)^(\infty ) 27^(n)(x-5)^(3n+2)(*,*). Use symbol \infty ...



Find the interval of convergence of \sum_(n=0)^(\infty ) 27^(n)(x-5)^(3n+2)(*,*). Use symbol \infty for infinity, \cup for combining intervals, and appropriate type of parenthesis " (",")", "[" or "] " depending on whether the interval is open or closed. Enter DNE if interval is empty.xin?


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