(Solved): For the recursively defined function \[ T(n)=6 T(n / 9)+n^{1 / 2} \] (keep in mind that \( n^{1 / ...

For the recursively defined function \[ T(n)=6 T(n / 9)+n^{1 / 2} \] (keep in mind that \( n^{1 / 2} \) is the square root of \( n \) ) with \( T(1)=32 \), the closed form for \( T(n) \) is given by: \( T(n)=A \times n^{B}+C \times n^{D} \), where \( A, B, C \), and \( D \) are constants, and \( B