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g-s-32000-s-s-8-s-40-a-use-bode-plot-sketches-to-design-a-compensator-so-that-pm-gt-45-deg-pa955
(Solved): G(s)=(32000)/(s(s+8)(s+40)) (a) Use Bode plot sketches to design a compensator so that PM>45\deg ...
G(s)=(32000)/(s(s+8)(s+40))(a) Use Bode plot sketches to design a compensator so that
PM>45\deg and
\omega _(Bw)>15ra(d)/(sec), where PM stands for phase margin and
\omega _(BW)is the closed-loop bandwidth (
25%). (b) Verify your design by drawing compensated Bode plots. Refine and verify your design again if necessary (15%).
