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/ iif-x-x-2-1-x-2-x-4-bf-x-2x-10-x-2-25-pa477
(Solved): IIf(x)=(x^(2)+1)/((x-2)(x+4)) Bf(x)=(2x-10)/(x^(2)-25) ...
IIf(x)=(x^(2)+1)/((x-2)(x+4)) Bf(x)=(2x-10)/(x^(2)-25)
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