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(Solved): in dire need ! Apply the loop rule to loop aedcba in the figure below. \[ \begin{array}{c} \mathcal ...
Apply the loop rule to loop aedcba in the figure below. \[ \begin{array}{c} \mathcal{E}_{2}=45 \mathrm{~V} \\ \left(I_{1} R_{1}\right)+\left(I_{2} r_{1}\right)-E_{1}+\left(I_{2} R_{2}\right)=0 \\ \left(I_{1} R_{2}\right)+\left(I_{2} r_{2}\right)-E_{1}+\left(I_{1} R_{2}\right)=0 \\ \left(I_{1} R_{2}\right)+\left(I_{2} r_{1}\right)-E_{2}+\left(I_{2} R_{3}\right)=0 \\ \left(I_{1} R_{3}\right)-\left(I_{2} r_{2}\right)+E_{2}+\left(I_{2} R_{3}\right)=0 \end{array} \]
Expert Answer
To apply loop rule in the given loop, we use K