In the figure, particle 1 of charge
q_(1)=4.00\times 10^(-5)C
and particle 2 of charge
q_(2)=3.70\times 10^(-4)C
are fixed to an
x
axis, separated by a distance
d=0.400m
. Calculate their net electric field
E(x)
as a function of
x
for the following positive and negative values of
x
, taking
E
to be positive when the vector
E
points to the right and negative when
E
points to the left. What is
E(-0.1)
? Submit Answer Tries
(0)/(10)
What is
E(-0.02)
? Submit Answer Tries
(0)/(10)
What is
E(0.05)
? Tries
(0)/(10)
What is
E(0.54)
? Submit Answer Tries 0/10