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In the figure, particle 1 of charge

`q_(1)=4.00\times 10^(-5)C`

and particle 2 of charge

`q_(2)=3.70\times 10^(-4)C`

are fixed to an

`x`

axis, separated by a distance

`d=0.400m`

. Calculate their net electric field

`E(x)`

as a function of

`x`

for the following positive and negative values of

`x`

, taking

`E`

to be positive when the vector

`E`

points to the right and negative when

`E`

points to the left. What is

`E(-0.1)`

? Submit Answer Tries

`(0)/(10)`

What is

`E(-0.02)`

? Submit Answer Tries

`(0)/(10)`

What is

`E(0.05)`

? Tries

`(0)/(10)`

What is

`E(0.54)`

? Submit Answer Tries 0/10