In the figure, particle 1 of charge
q_(1)=4.00\times 10^(-5)Cand particle 2 of charge
q_(2)=3.70\times 10^(-4)Care fixed to an
xaxis, separated by a distance
d=0.400m. Calculate their net electric field
E(x)as a function of
xfor the following positive and negative values of
x, taking
Eto be positive when the vector
Epoints to the right and negative when
Epoints to the left. What is
E(-0.1)? Submit Answer Tries
(0)/(10)What is
E(-0.02)? Submit Answer Tries
(0)/(10)What is
E(0.05)? Tries
(0)/(10)What is
E(0.54)? Submit Answer Tries 0/10