(Solved): Let \( y \) denote the number of broken eggs in a randomly selected carton of one dozen eggs. (a) C ...

Let \( y \) denote the number of broken eggs in a randomly selected carton of one dozen eggs. (a) Calculate and interpret \( \|_{V} \) : \[ \mathrm{H}_{y}= \] (b) In the long run, foe what percentage of cartons is the number of broken eggs lest than \( M_{y} \) ? Dods thas surprise you? Yes No (c) Explain why \( \mu_{y} \) is not equal to \( \frac{0+1+2+3+4}{5}=2.0 \), This computation of the mean is incomect bectuse it does not take into account the number of partially broken eggs. This computation of the mean is incorrect because the value in the denominator should equal the maximum y value. This computation of the mean is incorrect because it daes not take into account the probabilities with which the number of beoken eggs need to be weighted. This computation of the mean is incorrect because it includes zero in the numerator which should not be taken into account when calculating the mean. This computation of the mean is incorrect becouse at does not take into account that the number of broken eggs are all equally likely.