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(Solved): Let YExp(\lambda ), and define a random variable x based on Y in the following way: P(x=k)k=1,2,3 ...
Let Y?Exp(\lambda ), and define a random variable x based on Y in the following way:
P(x=k)k=1,2,3,dotsx?Geom(p)pp\lambda x=k, if k-1<=Y
Find P(x=k) for k=1,2,3,dots You should find x?Geom(p) for a value p; what is p in terms of \lambda ?